By Andrew J. T. Colin (auth.)
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A-------r--..... 10 The inverter ensures that when B = 0, the NAND gate actually receives a 1. Thus it only receives, and responds to, the combination of inputs (1, 1) when A = I and B = 0, as required by the truth table. Again, the special response is sometimes required to be a I, rather than a 0. This can be arranged by feeding the output of the NAND gate into another inverter. Il? 11 Stage 1: The NAND gate has two inputs, so the truth table will have three columns and four rows. We can draw a 'skeleton' table A B 0 0 0 1 0 Out Fundamentals of Computer Science 32 Stage 2: Both inputs are inverted, so the gate will respond when A = B = 0.
The two's complement notation described in the previous section is quite unsuitable either for fractions or for large numbers which lie beyond the permitted range. The standard way of handling both fractions and large numbers is called the 'floating-point' notation. Every value is represented by a pair of quantities called the 'mantissa' and the 'exponent'. The mantissa is a signed integer which lies within a given range. The exponent is a scale factor (or more accurately the log of a scale factor) which indicates by how much the mantissa should be multiplied to give a true value.
If any water runs out during this period you will know that you have won; but if none comes you can assume that you have lost. This fable illustrates several important aspects of the transmission of signals in logic networks. (I) (2) (3) The information transmitted at any time consists of 1 binary digit. We have not specified how large the current of water is to be, so a small current has the same meaning as a large one: a dribble brings the same news as a squirt in the eye. This means that it is easy for the transmission to stay accurate in spite of leaks, blockages, and so on - all that matters is that some water should get through.
Fundamentals of Computer Science by Andrew J. T. Colin (auth.)